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Early payments matter more than late payments. The formula is pretty simple: 1200*1.13^3.5 for the total amount of $1,840.58. If they just paid you, it's $250 less. If they paid you one year in, you'd subtract out that amount for the remaining 2.5 years at the same interest rate: 1200*1.13^3.5 - 250*1.13^2.5 and you get $1,501.24. So you see, it makes a difference when you got paid. The earlier they pay, the less interest accumulates. Here's a general loan calculator, though.
If you are compounding continuously, and he (I'll assume "he" here for convenience, but it works just as well for "she", "they", "it", etc.) paid you $250 at the end of 3½ years, then the formula to calculate the current value is:Value = P × ertWhere P is the principal ($1200), r is the annual rate (13% annually = 0 .13/year), and t is the time (3.5 years). e is Euler's number, which starts 2.71828.... Substituting in these values, we get Value = $1200 × e( 0 .13 × 3.5) = $ 1891.4080.. .So before he paid you back $250, the loan was worth $ 1891 .41, and after he paid you it was worth $ 1641 .41, or $ 441 .41 more now than when he borrowed the money. If you are compounding continuously, and he paid you $250 after (for example) one year, and it's been 2½ years since then, then you need to split the formula up into two time periods:Value1 = $1200 × e( 0 .13 × 1) = $ 1366 .5940... [$ 166 .59 interest in the first year] $ 1366 .59 − $250 = $ 1116 .59 [$ 1116 .59 is the new principal amount] Value2 = 1116 .59 × e( 0 .13 × 2.5) = 1545 .3947... [$ 428 .80 interest since last payment] In this example, he owes you $ 1545 .39 now, or $ 345 .39 more than when he borrowed the money. If you are compounding non-continuously, then the formula is a little different:Value = P × (1 + (r/n))ntAgain, P is the principal ($1200), r is the rate ( 0 .13/year), and t is the time (3.5 years), but now we've got a new variable, n, which is the number of times per year you are compounding. Let's say that you compound once a month; in this case, n = 12/year. So if he didn't pay you the $250 until the end of 3½ years, then the formula is as follows:Value = $1200 × (1 + ( 0 .13/12))(12 × 3.5)Solving this equation, we get $ 1886 .7855..., or $ 1886 .79 for the balance before he pays you $250, and $ 1636 .79 afterward. If you are compounding monthly and he paid you back $250 after 2 years, then we'd split it apart like above:Value1 = $1200 × (1 + ( 0 .13/12))(12 × 2) = $ 1554 .1415... [$ 354 .14 interest for the first two years) $ 1554 .14 − $ 250 .00 = $ 1304 .14 [$ 1304 .14 is the new principal amount] Value2 = $ 1304 .14 × (1 + ( 0 .13/12))(12 × 1.5) = $ 1583 .2744... [$ 279 .13 interest for the last 1½ years]In this example, he owes you $ 1583 .27 now. No matter how you slice it, he owes you approximately $1600, depending on how long ago he paid back the $250 and how often you compound the interest.
For Credit and finance solutions I visit this website where you can find all the solutions. :I need an online loan calculator on $1200 for 3 1/2 years @ 13% Interest....? ...Person has paid me a total of $250 max so far. Trying to figure out how much they owe me on the Balance Including the Interest? Follow 15 answers
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Hey i suppose its on simple interest basis(tahts what you shud get at the end of 3.5 yrs use this formulae I= NPR here N=42/12 yrs p=1200 R =13/100 so its 42*1200*13/12/100 = 546 so you should get 1200 + 546 at the end og 3.5 yrs!!
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